Question

For what value of k, do the equations 3x -y + 8 = 0 and 6x -k y = -16 represent coincident lines?

Answer 1

Answer:

remember in coincidence line,

$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$

Step-by-step explanation:

So, ATQ

a1 = 3, b1 = -1 c1 = 8

a2 = 6, b2 = -k c2 = 16

So,

$\frac{3}{6} = \frac{ - 1}{ - k} = \frac{8}{16}$

compare any two to get answer

I will compare a and b parts

$\frac{3}{6} = \frac{ - 1}{ - k}$

-3k = -6

k = 6/3

k = 2