Question

For what value of k do the equations 3x-y+8=0 and 6x-ky+16=0. represents
coincident lines​

Answer 1

Answer:

$Condition for coincident lines is - a1/a2 = b1/b2 = c1/c2 …(i) Given lines, 3x - y + 8 = 0 and 6x - ky + 16 = 0; Comparing with ax + by + c = 0; Here, a1 = 3, b1 = - 1, c1 = 8; a2 = 6, b2 = - k, c2 = 16; and From Eq. (i), 3/6 = 1/k = 8/16 1/k = 1/2 So, k = 2Read more on Sarthaks.com - https://www.sarthaks.com/878649/for-what-value-of-k-do-the-equations-3x-y-8-0-and-6x-ky-16-0-represent-coincident-lines$