Question

for what value of k does (k-12)x square + 2 (k-12)x+2=0 have equal roots?

Answer 1

Answer:14

Step-by-step explanation:

(k-12)^2+2 (k-12)x+2

Here,a=k-12,b=2 (k-12)&c=2

For equal roots,b^2-4ac=0

So, {2 (k-12)}^2-4 (k-12)2=0

4 (k-12)^2-8 (k-12)=0

(k-12)-2=0

k=14