Question

For what value of k does (k-12)xsquare +2 (k-12)x +2=0have equal roots

Answer 1

Here is your answer!!!!!!!!!!

Answer 2

b^2 - 4ac=0

0={2(k-12)}^2 - 2×2(k-12)

0={4(k^2+144-24k)}-4(k-12)

0=4k^2+576-96k-4k+48

0=4k^2-100k+624

0=k^2-25k+156

0=k^2-13k-12k+156

0=k(k-13)-12(k-13)

0=(k-12)(k-13)

k=12 or 13