Question

for what value of k does qadratic equation (k-5)x²+2(k-5)x+2=0 have equal roots

Answer 1

Hey!!!!

__________

We have

=> (k - 5)²x + 2(k - 5)x + 2 = 0

For equal roots D = 0

=> b² - 4ac = 0

=> {2(k - 5)}² - 4(k - 5)²(2) = 0

=> 4(k - 5)² - 8(k - 5)² = 0

=> 4(k - 5)²(1 - 2) = 0

=> -4(k - 5)² = 0

=> -4(k - 5)² = 0

=> (k - 5)² = 0

Thus k = 5 and k = 5

______________

Hope this helps ✌️