For what value of k does the equation 12x2+4kx+3=0 has real and equal roots?
Answers
Answered by
3
Hey
Here is your answer,
12x^2 + 4kx + 3 = 0
b^2 - 4ac = 0
(4k)^2 - 4 x 12 x 3 = 0
16k^2 - 146 = 0
16k^2 = 144
k^2 = 144/16
k^2 = 9
k = 3
Hope it helps you!
Here is your answer,
12x^2 + 4kx + 3 = 0
b^2 - 4ac = 0
(4k)^2 - 4 x 12 x 3 = 0
16k^2 - 146 = 0
16k^2 = 144
k^2 = 144/16
k^2 = 9
k = 3
Hope it helps you!
Similar questions