Question

For what value of k does the equation x + 2x + (k² + 1) = 0 has real and equal roots?​

Answer 1

Answer:

If equation have real and equal roots

then Discriminant of equation must be equal to zero

e.g D = b² - 4ac = 0

Now, here equation, x² +2x + (k² +1)=0

b = 2

a = 1

c = k² +1

Use this in above

D = (2)² -4(1)(k² +1) =0

4 -4k² -4 =0

K ² =0

K =0

Hence value of K = 0.

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