Question

For what value of k does the equations kx+ky=12 ; (k-3)x+3y=k​

Answer 1

Answer:

k= ±6

Step-by-step explanation:

given

kx+ky= 12..............(1)

(k-3)x+3y=k............(2)

on multipliying by 12/k in eqn (2)

[12((k-3)/k] x +[3×12/k] y= 12..........(3)

on comparing the coefficients of x and y from.

(1) and (3) ,

(12k-36)/k = k.

=> k²-12k+36=0

=> k=6......................(4)

36/k=k. => k= ±6.....................(5)

.. therefore k= ±6