For what value of k does the pair of equation given below has a unique solution
2x+Ky=6
4x+6y=0
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2x+ky=6
K=1 As x and y to be equal so equation is 2x+kx=6 Putting k=1 2x+x=6 3x=6 x=2 Y=2 K=1 K can have value[1,2..........n] Where n is infinity
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