For what value of 'k' does the pair of linear equations 2x - y - 3 = 0 and 2kx + 7y - 5 = 0 have a unique solution x = 1 & y = - 1? A) 3 B) 4 C) 6 D) - 6
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4
Answer:
6
Step-by-step explanation:
Given:
2x-y-3=0
2kx+7y-5=0
x=1 y=-1
substitute.....
2x1-(-1)-3=0
2kx1+7x(-1)-5=0
=> 2+1-3=0 ; 2k-7-5=0
=> 3-3=0 ; 2k-12=0
=> 0 ; 2k=12
=> k=12/2
=> k=6
Hope this helps you to understand easier.....
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