Question

for what value of k does the point (k, -3) lies on the line 3x-y = 6

Answer 1

(k,-3) point lies on the line. Therefore, it satisfies the equation.

3k+3=6

3k=3

k=1

Answer 2

Answer:

The required value $k$ is $1$.

Step-by-step explanation:

Concept:

A mathematical statement known as an equation is made up of two expressions joined together by an equal sign.

Given:

The equation is $3x-y=6$ and the point $(k,-3)$

To find:

The objective is to find out the value of $k$.

Solution:

The given equation $3x-y=6$

For the point, $(k,-3)$, $x=k$ and $y=-3$

Put the values of $x$ and $y$ in $3x-y=6$

⇒$3k-(-3)=6$

⇒$3k+3=6$

⇒$3k=6-3$

⇒$3k=3$

⇒$k=1$

Therefore the required value  $k$ is $1$.

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