Math, asked by murtujaansari5100, 9 months ago

For what value of k does the point (k,-3) lies on the line is 3x-y=6(k=1) Pls ans fast

Answers

Answered by anjilafaisal
3

Step-by-step explanation:

in the point (k,-3) , x=k and y= -3

3x − y = 6

3k − (-3)= 6

3k + 3 = 6

3k = 6-3 = 3

k = 3/3

k = 1

Answered by Dhi10g7
0

Answer:

3(k)-(-3)=6[k-1]

3k+3=6k-6

3k-6k=-6-3

-3k=-9

k=3

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