For what value of k does the point (k,-3) lies on the line is 3x-y=6(k=1) Pls ans fast
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Answered by
3
Step-by-step explanation:
in the point (k,-3) , x=k and y= -3
3x − y = 6
3k − (-3)= 6
3k + 3 = 6
3k = 6-3 = 3
k = 3/3
k = 1
Answered by
0
Answer:
3(k)-(-3)=6[k-1]
3k+3=6k-6
3k-6k=-6-3
-3k=-9
k=3
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