Question

For what value of k does the quadratic equation 4x^2-12x-k have no real root

Answer 1

Here is your answer :

4x^2-12x-k =0
By using b^2-4ac we will get
( 12)^2-4×4×k=0
144-16k=0
16k=-144
k=144/16
k=9
I hope this answers will help you.
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Answer 2

Answer:

Step-by-step explanation:

If they dont have real roots

Then D=0

b^2 - 4ac=0

(12)^2 - 4(4)(k) =0

144-16k=0

k=9