Question

For what value of k does the quadratic equation 4x2 – 1x – k = 0 has no real roots?​

Answer 1

Answer:

Value of k < (-1/16)

Step-by-step explanation:

Compare given Quadratic equation 4x²-1x-k=0 with ax²+bx+c=0 , we get

a = 4, b = -1 , c = -k

Discreminant (D)<0

/* Given roots not real */

=> b²-4ac<0

=> (-1)²-4×4×(-k)<0

=> 1+ 16k < 0

=> 16k < -1

=> k < -1/16

Therefore,

Value of k < (-1/16)

•••♪

Answer 2

Answer:

k less then -1/16

Step-by-step explanation:

has no real roots means D<0

then answer will be -1/16