Question

for what value of k , does the quadratic equation (k-12)x2 +2(k-1)x +2 =0
have equal roots?​

Answer 1

Step-by-step explanation:

b^2-4ac=0. [as the roots are equal]

(2k-k)^2-4(k-12)(2)=0

4k^2+k^2-4k^2-4k+8=0

-3k= -8

k=8/3

Answer 2

Answer:

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