Question

For what value of k,does the quadratic equation kx^2+(k-1)x+(k-1)=0 becomes a perfect square

Answer 1

Answer: K= 1/3 or 1

Step-by-step explanation:

A = k , b = (k-1) , c= (k-1)

Using Formula b^2-4ac=0

K^2+1-2k -4k(k-1) =0

K^2+1-2k -4k^2 +4k=0

3k^2 - 2k -1 =0

3k^2 - (3-1)k-1=0

3k^2 -3k+k-1=0

3k(k-1) +1(k-1)=0

(3k +1) (k-1) =0

K= 1/3 or 1