Question

For what value of k does the quadratic
equation x2 – 4kx + 4k=0 have equal positive
integer solutions?​

Answer 1

Answer:

Step-by-step explanation:

Hope it will help you.

Thank you.

Answer 2

Step-by-step explanation:

equal zeros can exists only when DISCRIMINANT(D) =b^2-4ac=0

in given quadratic equation a=1,b=-4k,c=4k

therefore b^2-4ac=(-4k)^2-4(1)(4k)=0

16k^2-16k=0

16k^2=16k

16k=16

k=16/16=1

k=1

THEREFORE YOUR ANSWER IS 1.

I hope you are satisfied by my answer.