Question

For what value of k does the Quadratic Equation X²-4kx+4k = 0 have equal positive integer solutions​

Answer 1

Answer is in Attachment !

Answer 2

Step-by-step explanation:

Given:

${x}^{2} - 4kx + 4k = 0$

To find: For what value of k does the Quadratic Equation have equal positive integer solutions.

Solution:

Tip: If Quadratic equation has equal positive roots, then D=0.

Step 1: Compare standard quadratic equation ax²+bx+c, a≠0 with given equation

here,

a=1

b=-4k

c=4k

Step 2: Put D=0

we know that D = b²-4ac

$( { - 4k)}^{2} - 4(4k)(1) = 0 \\ \\ 16 {k}^{2} - 16k = 0 \\ \\ 16k(k - 1) = 0 \\ \\ or \\ \\ k(k - 1) = 0 \\ \\ \bold{\red{k = 0}} \\ \\ or \\ \\ \bold{\green{k = 1}}$

Final answer:

Values of k are 0 or 1 for which the quadratic Equation x²-4kx+4k = 0 have equal positive integer solutions.

Hope it helps you.

To learn more on brainly:

find what k,-4is a zero of polynomial xpower2 -x (2k+2) ?

https://brainly.in/question/11131937

Factorise : mn(3m2 – 4n2) – np(4n2 – 3m2) + pm(15m2 – 20n2)

https://brainly.in/question/45559411