For what value of K, equation 9x^2 + 3Kx + 4 = 0 will have real unequal roots.
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Answer is k belongs to (-infinity, -4) union (4,infinity)
Look in the pic
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SOLUTION;___✍️
Here, a= 9, b= 3k, c= 4
therefore= D= b^2- 4ac= (3k)^2- 4×9×4= 9k^2-144
Roots are equal, if D=0
=9k^2-144=0
=9k^2=144
=9k^2-144=0
=k^2-16=0
=k^2-(4)^2=0
=(k+4) (k-4)=0
=k+4=0 or k-4=0
=k= 4 Answer.
MARK BRAINLIEST✓✓✓
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