Question

For what value of k equation has unique solution.
Kx+3y-2k=0
5x+ky-13=0​

Answer 1

Step-by-step explanation:

To find: Value of k for unique & no

solution

78

Step-by-step explanation:

kx +3y = k-3,

12x + ky = k

has a unique solution.

=> k/12 # 3/k # (k-3)/k

=> k ± 6

k² # 12k-36

=> (k - 6)² = 0

=> k # 6

3k-3

=> k # 6

All values of k other than ± 6 has

unique solution

(3k+1)x+3y -2=0 and

(k² +1)x +(k -2)y = 5 has no solution.

=> (3k + 1)/(k² + 1) = 3/(k - 2) # 2/5

=> 3k² -5k - 2 = 3k² + 3

=> k=-1

3/(k-2) # 2/5

3/(-3) # 2/5

=> k=-1 no solution