Question

for what value of k for which quadratic equation kx²-6x-2=0 has two real roots​

Answer 1

d= b^2-4 ac

= (-6)^2-4×k×-2

= 36+8k

if real and equal roots then d is equal to 0 that's why

d= 0

36+8k= 0

k=-36/8

or,, if roots are real and unequal then,,

d>0

36+8k>0

k> -36/8

I hope this will help uuu

Answer 2

Hey friend, Here is your answer.

Hope it will help you.

Please Please make me brainliest