for what value of k for which the following system of the linear equations has no solution 6x- 3y+ 10= 0 and 2x+ ky+ 9= 0
Answers
Answered by
2
for no solution, a1/a2 =b1/b2 ≠ c1/c2
here,a1/a2=6/2 b1/b2=3/k c1/c2=10/9
6/2=3/k≠10/9
6/2=3/k ⇒ 6k = 6
k=1
∴ 3/k=3/1
6/2=3/1
Answered by
7
Answer:
Your Answer
Hope it helps you
Attachments:
Similar questions
English,
7 months ago
Accountancy,
7 months ago
Hindi,
7 months ago
Chemistry,
1 year ago
English,
1 year ago