Question

for what value of k for which the following system of the linear equations has no solution 6x- 3y+ 10= 0 and 2x+ ky+ 9= 0

Answer 1

for no solution, a1/a2 =b1/b2 ≠ c1/c2

here,a1/a2=6/2 b1/b2=3/k c1/c2=10/9

6/2=3/k≠10/9

6/2=3/k       ⇒ 6k = 6

                       k=1

∴ 3/k=3/1

6/2=3/1

Answer 2

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