Question

For what value of k for which the given system of equations has infinitely many solution (1) 5x+2y = K , 10x+4y =3
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Answer 1

Answer:

The given system of equations is

5x+2y−k=0

10x+4y−3=0

This system of equation is of the form

a1x+b1y+c1=0

a2x+b2y+c2=0

where a1=5,b1=2,c1=−k 

and a2=10,b2=4 and c2=−3

For infinitely many solutions, we must have

a2a1=b2b1=c2c1 i.e., 105=42=−3−k⇒2