for what value of k for which the points A(9,k), B(4,-2) and C(3,-3) are collinear
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Answer:
k=3
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Find the value of K if the point A (2,3) ,B(4,K)and C(6,−3) are collinier
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Given that the points A(2,3),B(4,k) and C(6,−3) are collinear.
As we know that if three points are collinear then they will lie of a same plane and thus will not form a triangle.
Therefore,
Area of triangle formed by these points will be 0
Therefore,
Now,
Area of △ formed by these points =21×∣∣∣∣∣∣∣∣2463k−3111∣∣∣∣∣∣∣∣
Therefore,
∣∣∣∣∣∣∣∣2463k−3111∣∣∣∣∣∣∣∣=0
[2(k−(−3))−3(4−6)+1((−12)−6k)]=0
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