Question

For what value of k given equation have real and equal roots (k+1)x square - 2(k-1) x+1 =0

Answer 1

hey mate ‼️‼️

ur solution is in the attachment ⤴️⤴️

✌✌✌✌✌✌✌✌✌✌

#follow me

Answer 2

If it is real and equal roots D=0

b²-4ac=0

[2(k-1) ]²-4(k+1)*1=0

4(k²-2k+1)-4(k+1)=0

4k²-2k+4-4k-4=0

4k²-6k=0

2k(2k-3)=0

2k=0

----->k=0

2k-3=0

2k=3

------->k=3/2

Hope it helps.......

Pls mark me as brainliest ......