Question

for what value of k gor which x=3 is a solution of kx^2-2x-1=0​

Answer 1

Answer:

hey mate there's your answer

put x=3 in kx^2-2x-1=0 as it is its solution.

k(3)^2-2(3)-1=0

9k-6-1=0

9k-7=0

9k=7

k=7/9

hope it helps you.......................

Thank you!!!

Answer 2

Step-by-step explanation:

$k {x}^{2} - 2x - 1 = 0$

for x = 3

$k {3}^{2} - 2 \times 3 - 1 = 0$

9k - 6 - 1 = 0

9k - 7 = 0

$k = \frac{7}{9}$

I hope u understood ..

good day