Math, asked by bapichowdhury9153, 1 year ago

For what value of k is -3 a zero of the poynomial x2 + 11 +k

Answers

Answered by Anonymous
6
7Hello dear user ....

Your Answer is here..
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Given x = -3

If one of the zeros of Polynomial x^2 + 11 + k

Therefore , it Will satisfy the above Polynomial .
Now , we have -

=> (-3)^2 + 11 + k

=> 9 + 11 = k

=> k = 11 - 9

=> k = 2

so finally the value of k is 2 .

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hope \:  \: its \:  \: helps \:  \: you



Anonymous: :)
Answered by AdorableAstronaut
34

\huge{\underline{\mathfrak{Answer :}}}

Given = The value of X, which is (-3).

To find = The value of K

Equation = x^2 + 11 + k  

Zero of the polynomial =

x^2 + 11 + k = 0

Let's substitute the given value of x,

(-3)^2 + 11 + k = 0

9 + 11 + k = 0

20 + k = 0

k = - 20

Verification :

(-3)^2 + 11 + (-20)

9 + 11 - 20 = 0

Hence, the value of k is - 20.

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