For what value of k is -3 a zero of the poynomial x2 + 11 +k
Answers
Answered by
6
7Hello dear user ....
Your Answer is here..
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Given x = -3
If one of the zeros of Polynomial x^2 + 11 + k
Therefore , it Will satisfy the above Polynomial .
Now , we have -
=> (-3)^2 + 11 + k
=> 9 + 11 = k
=> k = 11 - 9
=> k = 2
so finally the value of k is 2 .
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Your Answer is here..
_____________________________
Given x = -3
If one of the zeros of Polynomial x^2 + 11 + k
Therefore , it Will satisfy the above Polynomial .
Now , we have -
=> (-3)^2 + 11 + k
=> 9 + 11 = k
=> k = 11 - 9
=> k = 2
so finally the value of k is 2 .
___________________________
Anonymous:
:)
Answered by
34
Given = The value of X, which is (-3).
To find = The value of K
Equation = x^2 + 11 + k
Zero of the polynomial =
x^2 + 11 + k = 0
Let's substitute the given value of x,
(-3)^2 + 11 + k = 0
9 + 11 + k = 0
20 + k = 0
k = - 20
Verification :
(-3)^2 + 11 + (-20)
9 + 11 - 20 = 0
Hence, the value of k is - 20.
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