Question

For what value of k , is the polynomial ( 2x⁴ + 3x³ + 2kx² + 3x + 6 ) exactly divisible by ( x+ 2 )?

Answer 1

Answer:

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Step-by-step explanation:

x+2= 0 = -2

2[-2]^4+3[-2]^3+2k[-2]^2+3[-2]+6=0

32-24+8k-6+6=0

8k=8

k=1

Answer 2

Answer:

k=-1

Step-by-step explanation:

2(-2⁴)+3(-2³)+(2k(-2))²+3(-2)+6=0

32-24+8k-6+6=0

8+8k=0

8k= -8

k= -1