Question

For what value of k is the polynomial 2x⁴+3x³+2kx²x3+6 xactly divisible by (x+2)?

Answer 1

Answer:

k = -7/12

Step-by-step explanation:

( x+2 ) is a factor of given eqn.

Therefore -2 is a root of eqn

2(-2)^4 + 3(-2)^3 + 2k (-2)^2 × 3 + 6 = 0

2(16) - 3(8) + 24k + 6 = 0

8 + 24k + 6 = 0

24k + 14 = 0

k = -7/12