Question

For what value of k, is the polynomial 3(x^4) + 2(x^3) - 4k(x^2) - 6x +6 exactly divisible by (x + 2) ? *

Answer 1

Using Remainder Theorem

(x + 2) = 0

x = -2

Therefore, 2x³ - 4kx² - 6x + 6 = 0 If, x = -2

Substituting x = -2

-16 - 16k + 12 + 6 = 0

2 - 16k = 0

k = 1/8