Question

for what value of K, is the polynomial p (x) =2×3-k×2+ 3x+10exactly divisble by (x+2)

Answer 1

since (x+2) is a factor of p(x)
so x= -2
putting x= -2 in p(x)=6 - 2k+3x+10=0
6-2k+3(-2)+10=0
10-2k=0
2k=10
k=5
hence the value of k is 5

Answer 2

Hey

Here is your answer,

Given that p(x) = 2x^3 - kx^2 +3x +10 is exactly divisible by (x+2).

X+2=0
X=-2

Substitute the value of x in the polynomial to find the value of k.

2x^3 - kx^2 +3x +10 =0
2 x (-2)^3 - k x (-2)^2 +3 x (-2) +10 =0
2 x (-8) - k x 4 -6 +10=0
-16 - 4k +4=0
-4k -12=0
-4k = 12
k = 12/-4
k = -3

Hope it helps you!
Plz mark it as brainliest answer!