Math, asked by bhupendratripathi50, 9 months ago

for what value of K, is the polynomial x5-3x4-kx3+3kx2+2kx+4 exactly divisible by (x-2)​

Answers

Answered by amulyasaxena
4

Answer:

Heya Friend

Here's your answer

x5 - 3x4 –kx3 + 3kx2 + 2kx + 4

Putting x=2.

(2)^5-3(2)^4-k(2)^3+3k(2)^2+2k(2)+4=0

32-48-8k+12k+4k+4=0

8k-8=0

k=1

Hope it helps

Plzzzz.. mark  e as brainliest, plzzzz..

Step-by-step explanation:

Similar questions