Question

For what value of k is the solution of K+2x-x^2=0

Answer 1

so here is your answer
K+2x -x2=0
b2-2x+x2=0
b2-4ac=0
a=2
c=k
main solution
(-1)2-4(2)(k)=0
1-(4×2)(k)=0
1-8k=0
k=1/8
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