For what value of k, is (x+1) is a factor p(x)=〖kx〗^2-x-4?
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Answered by
5
Apply remainder theorem
=>x - 1 =0
=> x = 1
According to remainder theorem p(1) = 0 we get
Plug x = 1 we get
=> k(1)2 + 1+ 1 =0
=>k +1 + 1 =0
=> k + 2 = 0
=> k = - 2
=>x - 1 =0
=> x = 1
According to remainder theorem p(1) = 0 we get
Plug x = 1 we get
=> k(1)2 + 1+ 1 =0
=>k +1 + 1 =0
=> k + 2 = 0
=> k = - 2
noora35:
hey
Answered by
5
K = 3
As we get value of x -1
Put value in statement and write answer
Best of luck! !!!!!
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