For what value of k;k+2, 4k-6, 3k-2 are three consecutive terms of an A. P.?
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the comman o of the AP is always same
therefore,
A2-A1= A3 - A2
k+2-k = 4k -6-(k+2)
2 = 3k -8
k =10/3
therefore,
A2-A1= A3 - A2
k+2-k = 4k -6-(k+2)
2 = 3k -8
k =10/3
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