Question

For what value of 'k', k-3,2k+1,4k+3 are in A.P?​

Answer 1

if,

the three are in ap,

the first term a = k-3

common difference d= 4k+3- 2k-1= 2k+2. and 2k+1-k+3= k+4

since the common difference is always same,

thus,

k+4=2k+2

4-2=2k-k

2=k