Question

For what value of 'k', k-3, 2k+1, & 4k+3 are in AP *​

Answer 1

Answer:

k=2

Step-by-step explanation:

if k-3, 2k+1 and 4k+3 are in AP then

(2k+1) - (k-3) = (4k+3) - (2k+1)

2k+1-k+3 = 4k+3-2k-1

k+4 = 2k+2

2k-k = 4-2

k= 2