Question

for what value of k linear equation have infinitely many solution 2x-3y=7 (k+1)x-(1-2k)y=(5k-4)

Answer 1

Step-by-step explanation:

2x-3y-7=0

(k-1)x-(1-2)y-(5k-4)=0

2/(k-1) = 3/(1-2) = 7/(5k-4)

by cross multiplication

2-4=3k-3 15k-12=7-14

-2+3=3k. 15k= -7+12

1/3=k. k= 5/15=1/3

I. e. value of k that satisfies both condition is k= 1/3

this value the pair of linear equation has infinite solution

Answer 2

Step-by-step explanation:

condition of infinite solutions

a1/a2=b1/b2=c1/c2

then according to question

2/k+1=3/1-2k=7/5k-4

taking 2/k+1=3/1-2k

2-4k=3k+3

7k=-1

k=-1/7