Math, asked by boby81903, 10 months ago

For what value of k, n=a is a solution of equation x^2-(a+b)n+k=0

Answers

Answered by pulakmath007
0

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Step-by-step explanation:

Since

x=a is a solution of equation x^2-(a+b)x+k=0

So

a^2-(a+b)a+k=0

-ab + k = 0

k = ab

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