Math, asked by Karanbhutna47, 1 year ago

FOR WHAT VALUE OF K...........NO SOLUTIONS


3X-4Y+7=0 , KX+3Y-5=O

2X-KY+3=0,3X+2Y-1=0

Answers

Answered by agclasher
2
Thus so

THE ANS FOR 1 .

➡ THE CONDITION REQUIRED FOR NO SOLUTION IS

. A1 / A2 = B1 / B2 ≠ C1 / C2

. 3 / K = - 4 / 3 ≠ 7 / -5
.
. K = 9 / - 4
.
. K ≠ - 15 / 7


THE ANS FOR 2 .

➡ THUS THE CONDITION REQUIRED IS

. A1 / A2 = B1 / B2 ≠ C1 / C2

. 2 / 3 = - K / 2 ≠ 3 / 1

. K = - 4 / 3

. K ≠ - 6

Hope it helps

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