Question

for what value of k of 3x-y-5=0 ; 6x-2y-k=0 has no solutions​

Answer 1

Answer:

has no soloition means have no solution

Answer 2

Given equations:

3x - y - 5 = 0,

$a_1 = 3, b_1 = -1, c_1 = -5$

6x - 2y - k = 0

$a_1 = 6, b_1 = -2, c_1 = -k$

It has no solution, i.e

$\it \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$

Therefore,

$\rm \therefore \frac{3}{6} = \frac{-1}{-2} = \frac{-5}{-k}$

$\rm \implies \frac{1}{2} = \frac{1}{2} = \frac{5}{k}$

So, By cross multiplying,

$\rm \implies 5 \times 2 = 1 \times k$

$\rm \implies \bf k = 10$

Hence, value of k = 10