Question

for what value of
k quadratic equation
kn 2 – kn+1 = o has equal
roots​

Answer 1

Answer:

For k = 4, the given quadratic equation has equal roots.

Step-by-step explanation:

The quadratic equation is kx^2-kx+1=0kn²−kn+1=0

on Comparing with ax²+bx+c=0

ax²+bx+c=0

a = k, b = -k, c = 1

Now, for the equal roots, we have

$b {}^{2} - 4ac = 0 \\ k {}^{2} - 4 \times k = 0 \\ k {}^{2} - 4k = 0 \\ k(k - 4) = 0 \\ k = 0 \\ k = 4$

Now, for k =0, it will not be a quadratic equation. Hence, we can discard k =0

Therefore, for k = 4, the given quadratic equation has equal roots.

Answer 2

For k = 4, the given quadratic equation has equal roots.

Step-by-step explanation:

The quadratic equation is kx^2-kx+1=0kn²−kn+1=0

on Comparing with ax²+bx+c=0

ax²+bx+c=0

a = k, b = -k, c = 1

Now, for the equal roots, we have,

b²-4ac=0

k²-4k=0

k(k-4)=0

k=4

Now, for k =0, it will not be a quadratic equation. Hence, we can discard k =0

Now, for k =0, it will not be a quadratic equation. Hence, we can discard k =0Therefore, for k = 4, the given quadratic equation has equal roots.

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$itzDopeGirl❣$