Question

for what value of K, roots of the
quadratic equationx y²+k² = 2(k+1)y
are equal​

Answer 1

Answer:

k=-1 or y=0

Step-by-step explanation:

because i tried to make RHS zero

Answer 2

Answer:

-1/2

Step-by-step explanation:

For equal roots D = 0 =>> b² - 4ac = 0

=> 4(k+1)² - 4*1*k² = 0

=> k² + 2k + 1 - k² = 0

=> 2k+1 = 0

=> k = -1/2