Question

for what value of k system of equations x +2y =3 and 5x + Ky +7 =0 has unique solution based on 10th class

Answer 1

x+2y=3
5x+Kya=-7

a1=1 b1=2 c1=3

a2=5. b2=k. c2=-7

For unique solution this equation must have
=>a1/a2≠b1/b2

so, by this

1/5≠2/k
10≠k

So, the value of k can be any real no. but not 10.

@Altaf

Answer 2

Given:

system of equations x +2y =3 and 5x + Ky +7 =0 has unique solution.

To Find:

Value of k

Solution:

Condition for unique solution:

= a₁/a₂ ≠ b₁/b₂

for pair of equations,

x +2y =3 and 5x + Ky +7 =0

a₁ = 1   a₂= 5

b₁ = 2    b₂ = k

so,

= a₁/a₂ ≠ b₁/b₂

1/5 ≠ 2/k

k ≠ 10

Hence, for every value of k except 10 the pair of equations has a unique solution.