Question

for what value of 'K' the
4x3 +3x²-4x+k is exactly
divisible by (X-1)​

Answer 1

$\huge\boxed{\boxed{\fcolorbox{white}{pink}{Answer}}}$

To Find:

Value of 'K'

Given:

x-1 is a factor of $4{x}^{3}+3{x}^{2}-4x+k$

Solution:

Let,

x-1=0

x=1

$\Large\mathcal\orange{Substituting\: the\: value\: of\: x}$

$4{x}^{3}+3{x}^{2}-4x+k=0$

$4{(1)}^{3}+3{(1)}^{2}-4(1)+k=0$

$4+3-4+k=0$

$\Large\mathbb\pink{k=(-3)}$

Hope it helps úh