Question

For what value of k the equation ax²+6x+4=0 has equal roots​

Answer 1

$Question$

For what value of k the equation ax²+6x+4=0 has equal roots​

$answer$

Given : kx² + 6x + 4k = 0 and sum and product of roots are equal.

On comparing the given equation with ax² + bx + c = 0  

Here, a = k , b = 6 , c =  4k

Sum of roots = - b/a

Sum of roots = - 6/k

Product of roots = c/a

Product of roots = 4k/k

Product of roots = 4

Given : sum of roots = Product of roots

-6/k = 4

4k = - 6

k = -6/4

k = - 3/2

Hence, the value of k is - 3/2.

Answer 2

sin theta +cos theta =p. then find sin theta in terms of p