Math, asked by yashikarao2477, 9 months ago

For what value of (k) the equation have a unique solution
2x+3y=1,kx+5y=7

Answers

Answered by AlluringNightingale
8

Answer :

k ≠ 10/3

[ k € R - { 10/3 } ]

Note:

★ A linear equation is two variables represent a straight line .

★ The word consistent is used for the system of equations which consists any solution .

★ The word inconsistent is used for the system of equations which doesn't consists any solution .

★ Solution of a system of equations : It refers to the possibile values of the variable which satisfy all the equations in the given system .

★ A pair of linear equations are said to be consistent if their graph ( Straight line ) either intersect or coincide each other .

★ A pair of linear equations are said to be inconsistent if their graph ( Straight line ) are parallel .

★ If we consider equations of two straight line

ax + by + c = 0 and a'x + b'y + c' = 0 , then ;

• The lines are intersecting if a/a' ≠ b/b' .

→ In this case , unique solution is found .

• The lines are coincident if

a/a'=b/b'=c/c' .

→ In this case , infinitely many solutions are found .

• The lines are parallel if a/a' = b/b' ≠ c/c' .

→ In this case , no solution is found .

Solution :

Here ,

The given equations of straight lines are ;

2x + 3y = 1

kx + 5y = 7

The given equations can be rewritten as ;

2x + 3y - 1 = 0

kx + 5y - 7 = 0

Here ,

a = 2

a' = k

b = 3

b' = 5

c = -1

c' = -7

Now ,

For the given equations to have an unique solution a/a' ≠ b/b' .

Thus ,

=> a/a' ≠ b/b'

=> 2/k ≠ 3/5

=> 2 × (5/3) ≠ k

=> k ≠ 10/3

=> k € R - { 10/3 }

Hence ,

k can be any real number but not 10/3 .

Similar questions