Question

for what value of k the equation x2- 4x-k =0 has real distinct roots


PLEASE SOLVE THIS ITS URGENT​

Answer 1

Answer ⤵️

${x}^{2} - 4x - k = 0$

${b}^{2} - 4ac = 0$

${ - 4}^{2} - 4(1)(k) = 0$

$8 - 4k = 0$

$- 4k = - 8$

$k = \frac{8}{4} \\ \\ \\ k = 2$

$hence \: k = 2$

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