Question

for what value of k the expression is perfect square

​

Answer 1

Answer:

For k = –1 / 3 and K = 1 , the expression becomes perfect square .

Step-by-step explanation:

For perfect square , the discriminant should be equal to zero .

Hence ,

$d \: = { {b}^{2} } - 4ac \: = 0$

=) [ 2( k + 1 ) ]² – 4(k²) (4 ) = 0

=) 4k² + 4 + 8k – 16k² = 0

=) 12k² – 8k – 4 = 0

=) 12k² - 12k + 4k – 4 = 0

=) 12k ( k – 1 ) + 4 ( k – 1 ) = 0

=) ( 12k + 4 ) ( k – 1 ) = 0

=) k = – 1 / 3 and K = 1