Math, asked by 444h2s, 11 months ago

For what value of k, the following have infinitely many solutions :
2x+3y=k
[k-1]x+[k+2]y=3k

Answers

Answered by sakshi11255
6

hope it will help you

Attachments:
Answered by balajibalajio529
1

Answer:

k=7

Step-by-step explanation:

a1/a2=b1/b2=c1/c2

2/k-1=3/k+2=3/3k

2(k+2)=3(k-1)

2k+4=3k-3

2k-3k=-3-4

-k=-7

k=7

3(3k)=k(k+2)

9k=k2+2k

-k2=2k-9k

-k2=-7k

-k=-7

k=7

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