For what value of k, the following have infinitely many solutions :
2x+3y=k
[k-1]x+[k+2]y=3k
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Answer:
k=7
Step-by-step explanation:
a1/a2=b1/b2=c1/c2
2/k-1=3/k+2=3/3k
2(k+2)=3(k-1)
2k+4=3k-3
2k-3k=-3-4
-k=-7
k=7
3(3k)=k(k+2)
9k=k2+2k
-k2=2k-9k
-k2=-7k
-k=-7
k=7
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